# Bullet Underwater? | Max Du

IMPORTANT: PLEASE DO NOT TRY THIS AT HOME

The man was not killed in the GIF animation. Why? Water resistance.

Resistance not only exist in water, but also in air. It is just that we as human beings have muscles strong enough to deal with the resistance that air imposes on us. Try to punch underwater and feel the difference.

Muhammad Ali, who unfortunately passed away 4 months ago, had a famous poster (shown above) of himself in a punching position underwater. Regardless of their veracity, rumors were that Ali practiced underwater and benefitted from such training. If he were really able to punch underwater at a moderate speed, imagine how much power that would be equivalent to, given the fact that even bullets stop moving underwater shortly after being fired.

It turns out that the magnitude of the force of resistance is proportional to the square of the velocity [1]. The equation is shown as below:

Whereas k represents a positive proportionality constant, and v denotes the velocity at which object travels. It has a negative sign in this equation because resistance is always acting in the opposite direction of v [2].

Now trace back to 1st year of high-school physics and think about the projectile problems. What if air resistance is not ignored? What would be the velocity function, then, for a ball released above ground? This is where differential equations come into play.

The acceleration of an object dropped from some height would be:

Note that the Greek letter ρ here denotes the ratio between the proportionality constant and the mass of the object:  k/m . It is derived from Newton’s second law and the equation for resistance force [3].

With the new substitution method that I learned in this week’s lectures, I was able to obtain the velocity function, shown as below:

Note that in substitution method is used, with the substitution being u = v √ρ/g .

The terminal velocity is determined by taking the limit of the velocity function as t goes to positive infinity. It turns out that the tanh function inside the equation above approaches -1 as the time approaches positive infinity terminal speed approaches –g/ρ .

With all that said, you probably already miss the days “without air resistance.” I assume no one would like to solve these differential equations in order to play ring toss games. However, NASA does have a page for a similar problem. To read more, click here.

Works Cited:
[1][2][3]: Edwards, C. Henry, and David E. Penney. Elementary Differential Equations with Boundary Value Problems. Englewood Cliffs, NJ: Prentice Hall, 1993. 88-89. Print.

Images Used:

*Note that all the equations are generated with http://www.hostmath.com/

## 5 thoughts on “Bullet Underwater? | Max Du”

1. tkbarnet

I’m curious how much factoring in air resistance will really change the outcome of most simple physics problem?

2. margaretjhaviland

Last week coffee, this week ring toss and Muhammad Ali were used to help us understand resistance. I assume engineers would use this to consider the resistance of other amounts of gravity encountered in space or on distant planets? Or would it be used to figure out how to get the last bit of ketchup out of the bottle?

3. rickyyu1999

This example of Muhammad Ali is really good, because I think it interests people who are relatively new to the subject of resistance and velocity functions. Although this is a little more physics related, it would be really cool to see what kind of shapes and sizes objects minimized resistance.

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